Code
Country = ["China",'USA',"UK","France","German","Japan"]
print(Country)['China', 'USA', 'UK', 'France', 'German', 'Japan']
在Python中,用方括号[] 表示列表,用逗号分隔其中的元素。
Country = ["China",'USA',"UK","France","German","Japan"]
print(Country)['China', 'USA', 'UK', 'France', 'German', 'Japan']
索引从0开始,而不是从1开始。
print(Country[0])
print(Country[4])China
German
也可以从倒数第一个数向前访问
print(Country[-1])
print(Country[-2])
print(Country[-3])Japan
German
France
使用列表中的值
intro = f"Hello,I'm from {Country[0]}!"
print(intro)Hello,I'm from China!
num = [1,2,3,4,5,6,7,8,9]
print(num)
num[0] = 0
print(num)[1, 2, 3, 4, 5, 6, 7, 8, 9]
[0, 2, 3, 4, 5, 6, 7, 8, 9]
在列表末尾添加元素
追加(append())到列表末尾
num = [1,2,3,4,5,6,7,8,9]
print(num)
num.append(10)
print(num)[1, 2, 3, 4, 5, 6, 7, 8, 9]
[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]
可以先创建空列表,再用append逐个添加元素。
fruit = []
fruit.append("apple")
fruit.append("pear")
print(fruit)['apple', 'pear']
在列表中插入元素
使用insert()方法可在列表的任意位置添加元素
num = [1,2,3,4,5,6,7,8,9]
print(num)
num.insert(0,0)
num[1, 2, 3, 4, 5, 6, 7, 8, 9]
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
使用del 语句删除元素
num = [1,2,3,4,5,6,7,8,9]
del num[0]
del num[2]
num[2, 3, 5, 6, 7, 8, 9]
使用pop()方法删除元素
弹出pop() 方法删除列表末尾的元素
num = [1,2,3,4,5,6,7,8,9]
popped_num = num.pop()
num
popped_num9
删除任意位置的元素
也可以使用pop()方法删除列表中任意位置的元素,指定索引即可
num = [1,2,3,4,5,6,7,8,9]
fifth_num = num.pop(4)
num[1, 2, 3, 4, 6, 7, 8, 9]
根据值删除元素
num = [1,2,3,4,5,6,7,8,9]
hate_num = 4
num.remove(hate_num)
num[1, 2, 3, 5, 6, 7, 8, 9]
使用sort()方法永久排序
### 字母顺序
letters = ["a","r","k","n","v","z"]
letters.sort()
print(letters)
### 字母逆序
letters = ["a","r","k","n","v","z"]
letters.sort(reverse = True)
print(letters)['a', 'k', 'n', 'r', 'v', 'z']
['z', 'v', 'r', 'n', 'k', 'a']
使用sorted()函数临时排序
letters = ["a","r","k","n","v","z"]
sorted(letters)
sorted(letters,reverse = True)
print(letters)['a', 'r', 'k', 'n', 'v', 'z']
使用reverse()方法反向打印列表
letters = ["a","r","k","n","v","z"]
letters.reverse()
print(letters) #反向打印
letters.reverse()
print(letters) #恢复['z', 'v', 'n', 'k', 'r', 'a']
['a', 'r', 'k', 'n', 'v', 'z']
使用len()函数确定列表长度
letters = ["a","r","k","n","v","z"]
len(letters)6
for循环
注意避免缩进错误,如忘记缩进、忘记缩进额外的代码行、不必要的缩进、循环后不必要的缩进、遗漏冒号、
subjects = ["Chinese","Mathematics","English","Physics","Chemistry","Biology"]
for subject in subjects:
print(f"{subject}:")
print(f"{subject} is very important for students.\n")
print("day day up!")Chinese:
Chinese is very important for students.
Mathematics:
Mathematics is very important for students.
English:
English is very important for students.
Physics:
Physics is very important for students.
Chemistry:
Chemistry is very important for students.
Biology:
Biology is very important for students.
day day up!
range()函数创建列表for value in range(-3,3):
print(value)-3
-2
-1
0
1
2
numbers = list(range(-5,5,2))
numbers
squares = []
for value in range(1,11):
square=value**2
squares.append(square)
print(squares)[1, 4, 9, 16, 25, 36, 49, 64, 81, 100]
digits = list(range(0,10))
min(digits)
max(digits)
sum(digits)45
squares = [i**2 for i in range(1,10)]
squares[1, 4, 9, 16, 25, 36, 49, 64, 81]
列表的部分称为slice。
letters = ["a","r","k","n","v","z"]
# 左包含,右不包含
letters[0:3]
letters[3:5]
letters[:3] # 0,1,2
letters[:-2] # 从头到倒数第2之前1位
letters[2:] # 从第3到末尾
letters[-3:] # 从倒数第3到末尾
letters[::2] # 从头到尾每间隔2打印
letters[1::3]
# 遍历slice
for i in letters[:3]:
i.upper()
# 复制slice
字母 = letters[:] # 从头到尾
字母.append("X")
字母
letters.append("Y")
letters
#不使用slice
letters = ["a","r","k","n","v","z"]
letters
LETTERS = letters # 两种指向同一个列表
LETTERS.append("X")
LETTERS
letters
letters.append("Y")
LETTERS
letters['a', 'r', 'k', 'n', 'v', 'z', 'X', 'Y']
Python将不能修改的值称为不可变的。而不可变的列表称为元组(tuple)。元组使用圆括号()+逗号,标识。严格地说,元组是用逗号标识的,圆括号只是让元组看起来更整洁、更清晰,并不是必须的。
dimensions = (200,50,4)
dimensions
# dimensions[0] = 333 # 'tuple' object does not support item assignment
single = 9,
# single[0] = 3虽然元组的元素不能修改,但可以重新给表示元组的变量赋值
dimensions = (200,50,4)
dimensions
dimensions = 2,3,4,5
dimensions
for i in dimensions:
i